10=-2x^2+20.1

Solution for 10=-2x^2+20.1 equation:

10=-2x^2+20.1

We move all terms to the left:

10-(-2x^2+20.1)=0

We get rid of parentheses

2x^2-20.1+10=0

We add all the numbers together, and all the variables

2x^2-10.1=0

a = 2; b = 0; c = -10.1;
Δ = b2-4ac
Δ = 02-4·2·(-10.1)
Δ = 80.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{80.8}}{2*2}=\frac{0-\sqrt{80.8}}{4}
=-\frac{\sqrt{}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{80.8}}{2*2}=\frac{0+\sqrt{80.8}}{4}
=\frac{\sqrt{}}{4}
$